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SimplexPy.py
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185 lines (154 loc) · 5.83 KB
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"""
Copyright (c) 2021 Mbadiwe Nnaemeka Ronald ron2tele@gmail.com
This software is provided 'as-is', without any express or implied
warranty. In no event will the author be held liable for any damages
arising from the use of this software.
Permission is granted to anyone to use this software for any purpose,
including commercial applications, and to alter it and redistribute it
freely, subject to the following restrictions:
1. The origin of this software must not be misrepresented; you must not
claim that you wrote the original software. If you use this software
in a product, an acknowledgment in the product documentation must be
specified.
2. Altered source versions must be plainly marked as such, and must not be
misrepresented as being the original software.
3. This notice must not be removed or altered from any source distribution.
"""
from fraction import fraction
class SimplexPy(object):
@staticmethod
def _SimplexEngine(arr, optimal = True, optimal_col = 0):
key_col = 0 # starts from index 1 and 0 means null
key_row = 0 # starts from index 1 and 0 means null
main_row = None
pivot = {'row':0,'col':0}
# get the key row
count = 0
for row in arr:
if row[0] == 'P':
key_row = count + 1
break
count += 1
# get the key column
if optimal:
min_value = 0
count = 0
for col in arr[key_row-1]:
if type(col) is not str:
if col < min_value:
min_value = col
key_col = count + 1
count += 1
else:
key_col = optimal_col + 1
# get the pivot
smallest_postive_no = 0
count = 0
for row in arr:
divisor = row[key_col - 1]
if row[0] != 'P' and divisor != 0:
val = fraction(row[-1]) / divisor
if val > 0 and smallest_postive_no == 0:
smallest_postive_no = val
pivot = {'row': count + 1,'col': key_col}
elif val > 0 and val < smallest_postive_no:
smallest_postive_no = val
pivot = {'row': count + 1,'col': key_col}
count += 1
# sanitize the key row
val = arr[pivot['row'] - 1][pivot['col'] - 1]
for i in range(1, len(arr[pivot['row'] - 1])):
arr[pivot['row'] - 1][i] = fraction(arr[pivot['row'] - 1][i]) / val
# sanitize the key col
main_row = arr[pivot['row'] - 1]
count = 0
for row in arr:
divisor = row[key_col - 1]
if row[0] != arr[pivot['row'] - 1][0] and divisor != 0:
for i in range(1, len(row)):
arr[count][i] -= (main_row[i] * divisor)
count += 1
return arr
@staticmethod
def _IsOptimal(arr, no_variables):
is_optimal = True
col = 0
for row in arr:
if row[0] == 'P':
for i in range(1, no_variables + 1):
if row[i] > 0:
col = i
is_optimal = False
break
return is_optimal, col
@staticmethod
def _ShouldIterate(arr):
iterate = False
for row in arr:
if row[0] == 'P':
for i in range(1, len(row)):
if row[i] < 0:
iterate = True
break
return iterate
@staticmethod
def _HasArtificialVariable(arr, no_variables):
pos = no_variables
for row in arr:
if row[0] != 'P':
for i in range(1, len(row) - 1): # without the constant `b`
if row[i] < 0:
return True
return False
@staticmethod
def _ResolveResult(row, no_variables):
if row[0] == 'P':
return 'Pmax', row[-1]
pos = 0
for i in range(1, len(row) - 1): # without the constant `b`
if row[i] == 1:
pos = i
break
if pos > 0 and pos <= no_variables:
return 'x{}'.format(pos), row[-1]
if pos > 0 and pos > no_variables:
return 'w{}'.format(pos - no_variables), row[-1]
return ''
@staticmethod
def SolveEq(arr, no_variables):
artificial_var = SimplexPy._HasArtificialVariable(arr, no_variables)
arr = SimplexPy._SimplexEngine(arr)
while SimplexPy._ShouldIterate(arr):
arr = SimplexPy._SimplexEngine(arr)
if artificial_var:
optimal, col = SimplexPy._IsOptimal(arr, no_variables)
while not optimal:
arr = SimplexPy._SimplexEngine(arr, optimal, col)
optimal, col = SimplexPy._IsOptimal(arr, no_variables)
ans = {}
for row in arr:
res = SimplexPy._ResolveResult(row, no_variables)
if res:
ans[res[0]] = res[1]
# clean result
for n in range(1, no_variables + 1):
try:
ans['x{}'.format(n)]
except:
ans['x{}'.format(n)] = fraction(0)
for n in range(1, len(arr) + 1):
try:
ans['w{}'.format(n)]
except:
ans['w{}'.format(n)] = fraction(0)
return ans
if __name__ == '__main__':
# problem setup
problem = [
['w1',2,1,1,0,0,18],
['w2',2,3,0,1,0,42],
['w3',3,1,0,0,1,24],
['P',-3,-2,0,0,0,0]
]
result = SimplexPy.SolveEq(problem, 2) # where 2 is the total number of variables
print(result)